MAT244-2013F > MidTerm
MT, P1
Victor Ivrii:
Solve the following initial value problem:
\begin{equation*}
y'(t) = 1- y^2(t),\qquad y(0)=0.
\end{equation*}
Yangming Cai:
answer to p1
Xiaozeng Yu:
1
Xuewen Yang:
For Xiaozeng Yu,
Is there a problem with the sign change? from "plus" (2nd row) to "minus" (3rd row) ?
Xiaozeng Yu:
--- Quote from: Xuewen Yang on October 09, 2013, 10:47:45 PM ---For Xiaozeng Yu,
Is there a problem with the sign change? from "plus" (2nd row) to "minus" (3rd row) ?
--- End quote ---
no mistake. $d(\ln(1-y))/dt = -1/(1-y)$.
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