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**Quiz-6 / Re: Q6 TUT 5301**

« **on:**November 17, 2018, 05:34:28 PM »

Why 2k? It should just be k.

$\displaystyle \begin{array}{{>{\displaystyle}l}}

f( z) \ =\ \pi \ cot\ ( \pi z)\\

\\

=\frac{\pi cos( \pi z)}{sin( \pi z)}

\end{array}$

So clearly, f(z) has a pole when sin($\displaystyle \pi z) \ =\ 0$ which happens whenever z is any integer

This pole is order 1.

You are right , it was a rudimentary mistake. I have corrected my answer thanks