Author Topic: TT2A-P1  (Read 7765 times)

Victor Ivrii

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TT2A-P1
« on: November 20, 2018, 05:47:57 AM »
(a) Find the general solution of
\begin{equation*}
y''-4y=2\tanh (t).
\end{equation*}

(b) Find solution, such that $y(0)=0$, $y'(0)=0$.

Jiabei Bi

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Re: TT2A-P1
« Reply #1 on: November 20, 2018, 12:34:21 PM »
This is my answer, thx

Xu Zihan

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Re: TT2A-P1
« Reply #2 on: November 20, 2018, 01:16:03 PM »
Here is my answer, somewhere different from Jiabei's.
« Last Edit: November 20, 2018, 01:20:54 PM by Xu Zihan »

Zhiqiu Ye

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Re: TT2A-P1
« Reply #3 on: November 20, 2018, 01:32:04 PM »
This is my answer, it is little bit different than Jiabei's answer.

yukeqi957

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Re: TT2A-P1
« Reply #4 on: November 20, 2018, 01:55:31 PM »
this is my answer, a bit different from Jiabei,bi.

Victor Ivrii

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Re: TT2A-P1
« Reply #5 on: November 25, 2018, 12:31:30 PM »
Zhiqiu is right. No $\arctan $ in the answe.