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### Messages - Kathy Ngo

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##### MAT334--Lectures & Home Assignments / 2.6 Q22
« on: November 22, 2018, 12:16:49 PM »
Can someone show me how they did (a)?
I have no idea how I'm supposed to use (8 ) or (9) to solve.

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##### MAT334--Lectures & Home Assignments / 2.5 - Q23
« on: November 20, 2018, 12:18:52 AM »
Can anyone show me how they did part (a)?
I got a series but it's not the same as the solutions in the back of the textbook.

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##### MAT334--Misc / term test 2 coverage
« on: November 15, 2018, 12:00:12 AM »
I know the coverage of the upcoming term test is chapter 2, but I was just wondering does this includes sections 2.1.1 and 2.3.1?

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##### Quiz-3 / Re: Q3 TUT 5101
« on: October 14, 2018, 12:20:54 AM »
Fix $G(z)$ such that $G(z)=\ln|z|+i(Arg(z) + c_{0} +\pi)$ where $c_{0} \in \mathbb{R}$
let $x=\ln|z|$ and $y=(Arg(z) + c_{0} +\pi)$

Note that
$\forall z\in D, |z|\geq 0 \Rightarrow x=\ln|z|\in(-\infty, \infty)$
and
$\forall z\in D, Arg(z) \in (-\pi, \pi) \Rightarrow y=Arg(z) + c_{0} +\pi \in (c_{0} , c_{0}+2\pi)$
Therefore $G$ maps $D$ onto $\{x+iy: -\infty < x< \infty, c_{0} <y<c_{0}+2\pi\}$.

Suppose $G(z_{1}) = G(z_{2})$ then
$\ln|z_{1}|+i(Arg(z_{1}) + c_{0} +\pi)=\ln|z_{2}|+i(Arg(z_{2}) + c_{0} +\pi)$
therefore, we have
$\ln|z_{1}| = \ln|z_{2}|$
$Arg(z_{1}) + c_{0} +\pi = Arg(z_{2}) + c_{0} +\pi \Rightarrow Arg(z_{1})=Arg(z_{2})$
these two equations imply $z_{1} = z_{2}$, hence the mapping is one-to-one on $D$.

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##### MAT334--Misc / Difference Between Lecture Sections
« on: September 10, 2018, 10:25:31 PM »
How closely related are the different lecture sections?
If I were to miss a lecture that I'm enrolled in, can I attend another professors lecture to catch up on the missed material?
Are the midterm/tests the same for all lecture sections?

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