MAT244-2014F > MAT244 Math--Lectures

WW2 - Problem 1

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**Diane Sicsic**:

Hey! I'm having difficulties for the Problem 1 of WW2.

The answer I found is Phi = yx + x + ln[(xy)^-2], but it seems like it's not the correct one.

Anyone knows where I got wrong/how I can find the answer?

Thankss

**Jasonisgood**:

How did you arrive at this answer?

I got phi = xy + x + y - 5ln(y) - 5ln(x)

I got this by integrating 1 - 5/x + y with respect to x and then differentiating this result with respect to y and setting it equal to 1 - 5/y + x.

**Victor Ivrii**:

Diane is correct and Jason is almost correct (wrong coefficient). Using MathJax http://www.math.toronto.edu/courses/mat244h1/20131/about_mathjax.html one can write an answer much nicer

\begin{equation*}

xy+x+y-2\ln (xy)=C.

\end{equation*}

Input is

--- Code: ---\begin{equation*}

xy+x+y-2\ln (xy)=C.

\end{equation*}

--- End code ---

**Arash Jalili**:

Wouldn't the correct answer be yx + x +y -4ln|xy|?

**Victor Ivrii**:

--- Quote from: jaliliar on September 23, 2014, 11:33:14 AM ---Wouldn't the correct answer be yx + x +y -4ln|xy|?

--- End quote ---

Nope. I already confirmed that Diane is correct

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