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**Term Test 2 / Re: TT2-P3**

« **on:**November 20, 2018, 09:51:51 AM »

The attachment is my solution.

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I think that's true. By isolating the variables X and Y, we can get an differential equation of 1/(ay+b) dy = dx. Then, take the integral on both side, a log function of y can be obtained. After simplifying the equation, we can have an exponential function with the coefficient of 'a'. Convergence or divergence depends on the sign of 'a'.

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