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integrating factor

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**Blair Zhang**:

How to derive the integrating factor for function only depends on x?

**wuyuning**:

Here is one way to prove it.

We need to find a factor so that make the ODE become exact.

So μ(x, y)M(x, y) + μ(x, y)N(x, y)y = 0, if the equation is exact, then (μM)y = (μN)x.

Further more, Mμy − Nμx + (My − Nx)μ = 0. You are asking about integrating factor only depends on x, so it is safe to assume that μy = 0(taking derivative with respect to y). then we find that dμ/dx= μ(My − Nx)/N. If (My − Nx)/N is a function of x only, then there is an integrating factor μ that also depends only on x.

I hope this brief explanation helps. :)

**Victor Ivrii**:

Search and read before you write

http://forum.math.toronto.edu/index.php?topic=1242.0

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