Author Topic: About HA5  (Read 4471 times)

Victor Ivrii

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About HA5
« on: November 01, 2012, 05:10:42 AM »
Some of subproblems are just tricks:

Example: Decompose into full F.s. $\cos (mx)$. Answer: $\cos (mx)$ as it is one of the basic functions (however it would not be so if we decompose into $\sin$-F.s., or F.s with respect to $\sin((n+\frac{1}{2}x)$, $n=0,1,\ldots$.


What is the sum F.s. on $(-\infty,\infty) was discussed in http://www.math.toronto.edu/courses/apm346h1/20129/L16.html

Again see below:
« Last Edit: November 01, 2012, 05:13:06 AM by Victor Ivrii »

Chiara Moraglia

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Re: About HA5
« Reply #1 on: November 10, 2012, 04:07:41 PM »
I'm confused over why the sketches for the full Fourier series and the sine Fourier series are different. They have the same formula. I would have expected them both to look like the plot for the sine Fourier series. Thanks.

Zarak Mahmud

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Re: About HA5
« Reply #2 on: November 10, 2012, 05:07:56 PM »
I'm confused over why the sketches for the full Fourier series and the sine Fourier series are different. They have the same formula. I would have expected them both to look like the plot for the sine Fourier series. Thanks.

For the function $f(x) = x$? Yes I think they should look the same.

Victor Ivrii

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Re: About HA5
« Reply #3 on: November 10, 2012, 05:25:45 PM »
If we are decomposing into full F.S. $f(x)=x$ on interval $[-l, l]$ then it is the same as to decompose into sin-F.S. $f(x)=x$ on interval $[0, l]$.

But if we decompose into full F.S.  $f(x)=x$ on interval $[0, l]$ then we have different picture: function is $l$-periodic and exactly this is on the picture (note that bolder line shows graph on the original interval)