Author Topic: 2011 term test 2 Problem 3. d  (Read 3632 times)

Kun Guo

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2011 term test 2 Problem 3. d
« on: November 14, 2012, 10:41:56 PM »
ut−kuxx=0 for x∈(0,π)
with the boundary conditions ux(0,t)=0 and u(Ï€,t)=0 and the initial condition u(x,0)=x.

Part d) Write the solution in the form of a series.

If we use separation of variables, U=X*T, I found that T0 is t dependent. Then A0*T0 cannot not just a constant or zeor(A0 is for X).
Are there any mistakes regarding that part in both solutions poster last year?

Victor Ivrii

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Re: 2011 term test 2 Problem 3. d
« Reply #1 on: November 15, 2012, 01:33:06 AM »
If we use separation of variables, U=X*T, I found that T0 is t dependent. Then A0*T0 cannot not just a constant or zeor(A0 is for X).
Are there any mistakes regarding that part in both solutions poster last year?

Your observation here is wrong and solutions are correct $X_0(t)T_0(t)= \cos(x/2) e^{-\frac{1}{2}t}$ satisfies boundary conditions.

Kun Guo

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Re: 2011 term test 2 Problem 3. d
« Reply #2 on: November 15, 2012, 11:49:27 AM »
Yes I got X0(t)T0(t)=cos(1/2*x)*exp(-1/2*t). But one solutions posted last year have either 0 or pi/2...

Victor Ivrii

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Re: 2011 term test 2 Problem 3. d
« Reply #3 on: November 15, 2012, 12:46:45 PM »
Yes I got X0(t)T0(t)=cos(1/2*x)*exp(-1/2*t). But one solutions posted last year have either 0 or pi/2...

So what? Someone posted a wrong solution.