Author Topic: How to find the eigenvector and determine type, special case.  (Read 1292 times)

Sheng Zang

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How to find the eigenvector and determine type, special case.
« on: December 07, 2014, 01:50:12 PM »
I got a question like this,
As I solved, I find the critical point is (0,0) and A= (0                 1)
                                                                          (-6x^2+8     0)
after plug(0,0) into, it becomes (0, 1)
                                              (0, 0)
so, λ1=0=λ2, how to solve eigenvector and determine the type of critical point?

Thanks for help.
« Last Edit: December 07, 2014, 02:36:36 PM by Sheng Zang »

Victor Ivrii

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Re: How to find the eigenvector and determine type, special case.
« Reply #1 on: December 07, 2014, 02:29:43 PM »
your post is incomprehensible

How to find eigenvector? See Linear algebra course and Sections 7.1, 7.2 of our textbook

Sheng Zang

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Re: How to find the eigenvector and determine type, special case.
« Reply #2 on: December 07, 2014, 02:45:56 PM »
I mean forλ1=0, matrix is A=(0 1)  *(x1) =(0)
                                           (0 0)   (y1)    (0)
the eigenvector is (1,0) which is horizontal.

and since λ is repeated, i.e λ1=λ2=0,
we solve (0 1)  *(x2) =(1)
              (0 0)   (y2)    (0)
so, another eigenvector is (0,1), which is vertical.

Am I correct?

Victor Ivrii

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Re: How to find the eigenvector and determine type, special case.
« Reply #3 on: December 07, 2014, 03:09:35 PM »
Except $(0,1)$ is not an eigenvector but a generalized e.v.

Sheng Zang

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Re: How to find the eigenvector and determine type, special case.
« Reply #4 on: December 07, 2014, 03:28:50 PM »
Also what is the type of critical point?  proper or improper node? And how to draw pic?( I don't think this is as usual as we draw (im)proper node picture)

Victor Ivrii

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Re: How to find the eigenvector and determine type, special case.
« Reply #5 on: December 07, 2014, 03:33:48 PM »
Improper node. See in Textbook. Forum is not a substitution for it