Toronto Math Forum
MAT2442018F => MAT244Lectures & Home Assignments => Topic started by: Jiabei Bi on September 14, 2018, 03:06:08 PM

Hi,
I have a question for the first example from last night’s lecture. The condition is $y’=y²$ , $y(0) = 1$. I know how to get the solution. The answer is $y =1/(1t)$. But I am confused about the restriction of variable $t$. Why the variable t has to be less than $1$?
Thanks!

Solution "breaks" at $t=1$ and since initial condition is at $t=0$ we consider a maximal interval s.t.
1) solution does not break in it
2) it contains $t=0$