Toronto Math Forum
MAT244-2014F => MAT244 Math--Lectures => Topic started by: Min Zhang on September 23, 2014, 06:32:35 PM
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I have been reading the textbook and found the following part that I don't quite understand:
At the top of page 11, it says
By the chain rule the left side of Eq. (6) is the derivative of ln|p-900| with respect to t, so we have $d/dt\ ln|p-900| = 1/2$.
Then, by integrating both sides of Eq. (7), we obtain $\ln|p-900| = t/2+C$
So my questions are:
1. Why can we get those statements?
2. Why do we have to insert a constant number $C$?
Thank you very much!
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In virtue of elementary knowledge of Calculus I.