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### Messages - Aladdin Seaifan

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##### HA2 / Re: HA2 problem 1
« on: February 12, 2015, 01:28:04 PM »
Im very confused on part c) you have used the initial conditions with x=2t, shouldn't it be x=-4t? since in c) we are told v=-4 so then the set of equations would change?

I'm pretty sure you're correct as well lol. And the question never told us to solve for it, although it would be good practice.
My answer to that question is c).
I'll post my attempt to the solutions after the midterm since I my answers are different.

2
##### HA2 / Re: HA2 problem 1
« on: February 11, 2015, 08:51:29 PM »
Hey I'm looking over your solutions for #2 and either I spot a mistake or I'm misunderstanding something.

I agree with what you have for ( 8 )
I follow up to step ( 10 ) .
But from ( 10 ) to ( 11 ) , you got rid of the negative sign for some reason. I don't think the negative signs simply cancel out.

When I leave things as is, my answer is $u(x,t) = \frac{1}{3}(cos(x + 3t) - 5cos(5x - 15t))$

3
##### Test 1 / Test 1 covered materials?
« on: February 11, 2015, 12:39:30 PM »
Up to what week of lectures will the test cover?

Thanks

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