Author Topic: Section4.4 Q11  (Read 587 times)

Zhihao Zuo

  • Jr. Member
  • **
  • Posts: 5
  • Karma: 3
    • View Profile
Section4.4 Q11
« on: October 31, 2018, 05:04:27 PM »
Find the solution of the given initial value problem:
y'''-y''+y'-y=sec(t), y(0)=2, y'(0)= -1, y''(0)=1

The solution manual writes "...with t(0)=0. Thus y(0) = c1+c2=2, y'(0)..." What does c1,c2 stand for?

Victor Ivrii

  • Administrator
  • Elder Member
  • *****
  • Posts: 2550
  • Karma: 0
    • View Profile
    • Personal website of Victor Ivrii
Re: Section4.4 Q11
« Reply #1 on: October 31, 2018, 07:37:42 PM »
What does c1,c2 stand for?
probably some constants.