TUT0201 MAT244 QUIZ 1

[Jiayue Wu]

  Welcome to discuss

Slove $$y'=ysinx$$
it is seperable. i.e. $$\frac{dy}{dx}=y*sinx$$
rearrange it. $$\frac{dy}{y}=sinx*dx$$
integrating both side. $$In|y|=-cosx+C_{1}$$
Finally we get: $$y = C*e^{-cosx}$$where$$ C > 0$$