Author Topic: quiz3 0501  (Read 288 times)

Hongling Liu

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quiz3 0501
« on: October 11, 2019, 02:02:10 PM »
    y‘’ - 2y’ - 2y = 0
    Solution:
    r^2 - 2r - 2= 0
    r1 = 1 +√3
    r2 = 1- √3
    y = C1⋅e^(1+√3)⋅t + C2⋅e^(1-√3)⋅t