Author Topic: Quiz 3 TUT 0401  (Read 104 times)

Jiayue Wu

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Quiz 3 TUT 0401
« on: February 12, 2020, 05:54:31 PM »
Question: Evaluate the given integral using Cauchy's Formula or Theorem.
$$\int_{|z| = 2} \frac{e^z}{z(z-3)}dz$$
Answer:
We can find that on the region $|z| = 2$, $F(z) =  \frac{e^z}{z(z-3)}$ not continuous at z = 0. Therefore I'll apply Cauchy's Formula.
$$\int_{|z| = 2} \frac{e^z}{z(z-3)}dz = \int_{|z| = 2} \frac{e^z /(z-3)}{z}dz$$
$$\implies f(z) = \frac{e^z}{z-3}, f(0) = -\frac{1}{3}$$
$$\int_{|z| = 2} \frac{e^z}{z(z-3)}dz = 2\pi i f(0) = -\frac{2\pi i}{3}$$