Author Topic: Handout 4b  (Read 1005 times)

Mark Meschino

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Handout 4b
« on: October 07, 2014, 08:54:40 PM »
Hi Professor,
I have a question regarding Handout 4b.  From Handout 4b, I understand Step 1 where we make the substitution in order to get the characteristic polynomial, however I am not quite sure what we are trying to accomplish in the second step. Could you maybe clarify this for me?

Thanks
Mark

Victor Ivrii

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Re: Handout 4b
« Reply #1 on: October 07, 2014, 11:59:34 PM »
On the second step we describe constant coefficient equation we get after substitution.