Author Topic: Julia Set  (Read 507 times)

Laura Campbell

  • Newbie
  • *
  • Posts: 2
  • Karma: 0
    • View Profile
Julia Set
« on: March 14, 2017, 03:18:47 PM »

Thierry Serafin Nadeau

  • Newbie
  • *
  • Posts: 3
  • Karma: 0
    • View Profile
Julia Set
« Reply #1 on: March 15, 2017, 06:07:38 PM »
Turns out that there are 4D analogues to the 2D Julia sets which use quaternions ($i^2 = j^2 = k^2 = ijk = -1$) instead of regular complex numbers. Seeing as they're 4D they can only be visualised as 3D slices of the whole set, which end up looking quite a bit different than the regular Julia sets depending on the chosen slice.

Here's a link to a video which passes through multiple 3D slices of a quaternion Julia set: https://www.youtube.com/watch?v=VkmqT6MQoDE
And bellow is an image of such a slice.
« Last Edit: March 15, 2017, 06:12:37 PM by Thierry Serafin Nadeau »

leonoraboci

  • Newbie
  • *
  • Posts: 3
  • Karma: 0
    • View Profile
Re: Julia Set
« Reply #2 on: March 27, 2017, 11:19:20 PM »
Julia set with the parameter ยต taken from the center of the circle on top of the cardioid.

Andi

  • Newbie
  • *
  • Posts: 2
  • Karma: 0
    • View Profile
Re: Julia Set
« Reply #3 on: April 05, 2017, 12:56:26 AM »
Julia Sets:
zn+1 = c sin(zn)   zn+1 = c exp(zn)
zn+1 = c i cos(zn)   zn+1 = c zn (1 - zn)


A property of the the Julia Set is that if the domain of c is real numbers the the Julia Set it mirrored about the Real axis. If  c is a complex number with an imaginary component then then the symmetry is rotational at 180 degrees.