Author Topic: Another erf  (Read 1017 times)

Jingxuan Zhang

  • Elder Member
  • *****
  • Posts: 106
  • Karma: 20
    • View Profile
Another erf
« on: February 07, 2018, 06:19:32 AM »
In a post last year erf was given by
$$\text{erf}_1(z)=\sqrt{\frac{2}{\pi}}\int_0^z e^{-s^2/2} \,ds$$
I assume this is not equivalent to our erf, and in fact $\text{erf}(z/\sqrt{2})=\text{erf}_1(z)$. Am I right? How does this difference affect the solution, if any at all?
« Last Edit: February 07, 2018, 06:39:36 AM by Victor Ivrii »

Victor Ivrii

  • Administrator
  • Elder Member
  • *****
  • Posts: 2553
  • Karma: 0
    • View Profile
    • Personal website of Victor Ivrii
Re: Another erf
« Reply #1 on: February 07, 2018, 06:44:17 AM »
Yes, the canonical definition is as in the textbook.