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### Messages - ziyao hu

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##### Chapter 3 / Difference between what we talk about in Chapter 3 & 4
« on: October 19, 2016, 10:54:31 AM »
I'm wondering why in Chapter 4, we need 2 boundary conditions, if we can solve the problem with only 1 b.c. just as the problem 5 in Assignment 5?
Pictures shown as below,

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##### Chapter 2 / Re: HA #4 general
« on: October 18, 2016, 07:05:46 PM »
So what's the meaning of "up to constants that will not affect u(x,t)"

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##### Chapter 2 / HA #4 general
« on: October 17, 2016, 06:15:10 PM »
I saw the solution professor posted last year, as the folloing picture.
Can we just assume constant = 0 and then put one at the end of the solution?

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##### Q3 / Re: Q3
« on: October 17, 2016, 12:49:32 PM »
If the boundary condition was $u|_{x=0}=k(t)$ then there would be no integration, thus no constant and in general no continuity.

Otherwise yes: you need to choose a correct constant but if so, it will be explicitly said so

Does it mean that if the boundary condition was $u|_{x=0}=k(t)$ then there would be in general no continuity. We do not necessarily need to make it continuous.
But in this problem, we need to select constant to make it continuous?

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