MAT244--2018F > MAT244--Lectures & Home Assignments

First example from Thursday’s lecture

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**Jiabei Bi**:

Hi,

I have a question for the first example from last night’s lecture. The condition is $y’=y²$ , $y(0) = 1$. I know how to get the solution. The answer is $y =1/(1-t)$. But I am confused about the restriction of variable $t$. Why the variable t has to be less than $1$?

Thanks!

**Victor Ivrii**:

Solution "breaks" at $t=1$ and since initial condition is at $t=0$ we consider a maximal interval s.t.

1) solution does not break in it

2) it contains $t=0$

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