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MAT244--2019F
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TUT0602 Quiz4
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Topic: TUT0602 Quiz4 (Read 6398 times)
Yuchen Cong
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TUT0602 Quiz4
«
on:
October 19, 2019, 05:11:25 PM »
Question:
2y''+2y+1=0
Solution:
2r
2
+2r+1=0
r=[-2+-((-2)
2
-(4)(2)(1))
(1/2)
]/2(2)
r=[-2+-(-4)
(1/2)
]/4
r=-(1/2)+-(1/2)i
λ=-(1/2), µ=1/2
y(t)=C1e
-(1/2)t
cos(1/2)t+C2e
-(1/2)t
sin(1/2)t
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MAT244--2019F
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TUT0602 Quiz4