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Author Topic: Section4.4 Q11  (Read 1431 times)

Zhihao Zuo

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Section4.4 Q11
« on: October 31, 2018, 05:04:27 PM »
Find the solution of the given initial value problem:
y'''-y''+y'-y=sec(t), y(0)=2, y'(0)= -1, y''(0)=1

The solution manual writes "...with t(0)=0. Thus y(0) = c1+c2=2, y'(0)..." What does c1,c2 stand for?
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Victor Ivrii

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Re: Section4.4 Q11
« Reply #1 on: October 31, 2018, 07:37:42 PM »
Quote from: Zhihao Zuo on October 31, 2018, 05:04:27 PM
What does c1,c2 stand for?
probably some constants.
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