Toronto Math Forum

MAT334-2018F => MAT334--Tests => Quiz-2 => Topic started by: Victor Ivrii on October 05, 2018, 06:14:25 PM

Title: Q2 TUT 0301
Post by: Victor Ivrii on October 05, 2018, 06:14:25 PM
Determine whether the given infinite series converges or
diverges:
\begin{equation*}
\sum_{n=1}^\infty \Bigl(\frac{1+2i}{\sqrt{6}}\Bigr)^n.
\end{equation*}
Title: Re: Q2 TUT 0301
Post by: Meng Wu on October 05, 2018, 06:39:52 PM
By Ratio Test:
$$\begin{align}\sum_{n=1}^\infty \Biggl(\frac{1+2i}{\sqrt{6}}\Biggl)^n &= \lim_{n\to\infty}\Biggl|\frac{\Big(\frac{1+2i}{\sqrt{6}}\Big)^{n+1}}{\Big(\frac{1+2i}{\sqrt{6}}\Big)^{n}}\Biggr|\\&=\lim_{n\to\infty}\Biggl|\frac{1+2i}{\sqrt{6}}\Biggr|\\&=\Biggl|\frac{1+2i}{\sqrt{6}}\Biggr|\\&=\sqrt{\Big(\frac{1}{\sqrt{6}}\Big)^2+\Big(\frac{2}{\sqrt{6}}\Big)^2}\\&=\sqrt{\frac{5}{6}}<1\end{align}$$
Therefore,  the given infinite series converges.