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MAT244--2018F
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Q3 TUT 0101
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Topic: Q3 TUT 0101 (Read 5257 times)
Victor Ivrii
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Elder Member
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Q3 TUT 0101
«
on:
October 12, 2018, 06:02:55 PM »
Find the general solution of the given differential equation.
$$y''-2y'-2y=0.$$
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Yulin WANG
Full Member
Posts: 17
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MAT244H1 2018F
Re: Q3 TUT 0101
«
Reply #1 on:
October 12, 2018, 06:05:50 PM »
In the attachment.
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Yiting Zhang
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Karma: 8
Re: Q3 TUT 0101
«
Reply #2 on:
October 12, 2018, 06:11:17 PM »
$$y′′−2y′−2y=0$$
$$r^2−2r−2=0$$
$$r = \frac{−b \pm \sqrt{b^2−4ac}}{2a}$$
$$r_1=1+\sqrt{3}, r_2=1−\sqrt{3}$$
$$y=c_1e^{(1+\sqrt{3})t}+c_2e^{(1-\sqrt{3})t}$$
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Victor Ivrii
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Re: Q3 TUT 0101
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Reply #3 on:
October 12, 2018, 07:26:07 PM »
LOL: Yulin, you typed it to produce in the end png. Why not directly into forum?
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