Toronto Math Forum
MAT3342018F => MAT334Lectures & Home Assignments => Topic started by: Kris on December 03, 2018, 11:52:10 PM

Can someone help me solve this problem?

Here is how I think about this question.
Let $h = fg$, and we know that h is analytic. Therefore $\lefte^ {fg} \right = e^ {Reh} = e^0 = 1$, since $Ref = Reg$
So $\lefte^ {fg} \right = 1 $ and it implies that $e^ {fg}$ is constant which means $e^ {fg} = c$ so $fg = ln(c)$