Toronto Math Forum

MAT244--2019F => MAT244--Test & Quizzes => Quiz-4 => Topic started by: Yu Qi Huang on October 18, 2019, 02:12:16 PM

Title: Quiz 4 TUT 0702
Post by: Yu Qi Huang on October 18, 2019, 02:12:16 PM
Find the general solution for y'' - 6y' + 9y = 0.

Solution:
changing it into characteristic equation it becomes:
r^2 - 6r + 9 = 0
(r-3)^2 = 0
r = 3

Hence y(t) = c_1e^(3t) + c_2te^(3t)