Toronto Math Forum
MAT2442019F => MAT244Test & Quizzes => Quiz1 => Topic started by: Victorwoshinidie on September 28, 2019, 11:54:06 PM

μ(t) = e^∫2 dt = e^(2t)
Multiply both sides by μ(t):
e^(2t)y'  2e^(2)ty = e^(2t)e^(2t)
d/dt (e^(2t)y) = I
e^(2t)y = t+c(By integrating both sides)
y=(t+c)/(e^(2t))
y = (t+c)e^2t
Substitue y(0) = 2 into the equation above, then:
2 = (0 + c)e^0 = C*1
The solution to the IVP is y = (t+2)e^(2t)