Toronto Math Forum

MAT244--2019F => MAT244--Test & Quizzes => Quiz-1 => Topic started by: Jiayue Wu on September 27, 2019, 02:49:00 PM

Title: TUT0201 MAT244 QUIZ 1
Post by: Jiayue Wu on September 27, 2019, 02:49:00 PM
 ;D Welcome to discuss

Slove $$y'=ysinx$$
it is seperable. i.e. $$\frac{dy}{dx}=y*sinx$$
rearrange it. $$\frac{dy}{y}=sinx*dx$$
integrating both side. $$In|y|=-cosx+C_{1}$$
Finally we get: $$y = C*e^{-cosx}$$where$$ C > 0$$