MAT244--2019F > Term Test 2

Problem 1 (noon)

<< < (2/2)

Mingdi Xie:
This is my solution

Victor Ivrii:
$$
\boxed{  y= \Bigl(-\frac{1}{2}\ln (e^{2t}+1)+c_1 \Bigr)e^{t} + \Bigl( \arctan (e^t)+c_2\Bigr)e^{2t}. }
$$
 and
$$
\boxed{  y= \Bigl(-\frac{1}{2}\ln (e^{2t}+1)+\frac{1}{2}\ln (2)  \Bigr)e^{t} + \Bigl( \arctan (e^t)-\frac{\pi}{4}\Bigr)e^{2t}. }
$$

Navigation

[0] Message Index

[*] Previous page