APM346--2020S > Chapter 6

Laplace Equation Section 6.4

(1/1)

**Kuangyi Tang**:

In section 6.4, the topic about separation of variables.

I don't exactly understand why the constraint $$\Theta(0)=\Theta(2\pi)$$ gives the Eigen functions $\Theta_{s,n}(\theta)=sin(n\pi \theta)$and $\Theta_{c,n}(\theta)=cos(n\pi \theta)$. Shouldn't the condition produce the Eigen functions $\Theta_{s,n}(\theta)=sin(\frac{n \pi \theta}{2})$and $\Theta_{c,n}(\theta)=cos(\frac{n\pi \theta}{2})$ instead?

Since previously a similar problem $$\Theta'' + \lambda \Theta = 0 $$ $$\Theta(0)=\Theta(\alpha)$$ give the Eigen functions $sin(\frac{n\pi \theta}{\alpha} )$ $cos(\frac{n\pi \theta}{\alpha} )$ and the Eigenvalue$\lambda_n = (\frac{n \pi}{\alpha})$

P.S. I couldn't get the Quercus discussion to work

**Kuangyi Tang**:

I understand now, there is another constraint $$\Theta'(0)=\Theta'(2\pi)$$, but what does this condition mean physically?

**Victor Ivrii**:

It means that $\Theta $ is $2\pi$-periodic.

Navigation

[0] Message Index

Go to full version