MAT244-2013F > MidTerm

MT, P1

**Victor Ivrii**:

Solve the following initial value problem:

\begin{equation*}

y'(t) = 1- y^2(t),\qquad y(0)=0.

\end{equation*}

**Yangming Cai**:

answer to p1

**Xiaozeng Yu**:

1

**Xuewen Yang**:

For Xiaozeng Yu,

Is there a problem with the sign change? from "plus" (2nd row) to "minus" (3rd row) ?

**Xiaozeng Yu**:

--- Quote from: Xuewen Yang on October 09, 2013, 10:47:45 PM ---For Xiaozeng Yu,

Is there a problem with the sign change? from "plus" (2nd row) to "minus" (3rd row) ?

--- End quote ---

no mistake. $d(\ln(1-y))/dt = -1/(1-y)$.

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