Toronto Math Forum
Welcome,
Guest
. Please
login
or
register
.
1 Hour
1 Day
1 Week
1 Month
Forever
Login with username, password and session length
News:
Home
Help
Search
Calendar
Login
Register
Toronto Math Forum
»
MAT334--2020F
»
MAT334--Lectures & Home Assignments
»
Chapter 1
»
1.2 circles
« previous
next »
Print
Pages: [
1
]
Author
Topic: 1.2 circles (Read 3963 times)
Maria-Clara Eberlein
Jr. Member
Posts: 11
Karma: 0
1.2 circles
«
on:
September 23, 2020, 07:27:50 PM »
When we have are asked to find the locus of |z-p|=|z-q|, can we immediately say the perpendicular bisector of the line segment joining p and q, or must we plug in z=x+iy and solve to get x=0?
«
Last Edit: September 25, 2020, 12:11:12 AM by Maria-Clara Eberlein
»
Logged
shiyuancao
Jr. Member
Posts: 6
Karma: 0
Re: 1.2 circles
«
Reply #1 on:
September 24, 2020, 04:52:59 PM »
I think this depends on how you want to represent your solution. Both of them seems rational to me.
But $x$ does not necessarily to be $0$ since $p$ and $q$ are some arbitrary complex numbers.
Logged
Lubna Burki
Newbie
Posts: 2
Karma: 0
Re: 1.2 circles
«
Reply #2 on:
September 24, 2020, 07:34:11 PM »
I think it's enough to say that this looks like one of the Apollonius circles in which is row is 1 then a line is given (specifically the perpendicular bisector of the two foci).
Logged
Print
Pages: [
1
]
« previous
next »
Toronto Math Forum
»
MAT334--2020F
»
MAT334--Lectures & Home Assignments
»
Chapter 1
»
1.2 circles