MAT244--2018F > Quiz-3

Q3 TUT 0101

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Victor Ivrii:
Find the general solution of the given differential equation.
$$y''-2y'-2y=0.$$

Yulin WANG:
In the attachment.

Yiting Zhang:
$$y′′−2y′−2y=0$$
$$r^2−2r−2=0$$
$$r = \frac{−b \pm \sqrt{b^2−4ac}}{2a}$$
$$r_1=1+\sqrt{3}, r_2=1−\sqrt{3}$$

$$y=c_1e^{(1+\sqrt{3})t}+c_2e^{(1-\sqrt{3})t}$$

Victor Ivrii:
LOL: Yulin, you typed it to produce in the end png. Why not directly into forum?

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