### Author Topic: FE-P3  (Read 5629 times)

#### Victor Ivrii

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##### FE-P3
« on: April 11, 2018, 08:42:26 PM »
Find the general solution of
\begin{equation*}
y''' -6y'' +11y'- 6y=2\frac{e^{3x}}{e^x+1} .
\end{equation*}

#### Tim Mengzhe Geng

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##### Re: FE-P3
« Reply #1 on: April 11, 2018, 11:37:34 PM »
First we find the solution for the homogeneous system

y^{(3)}-6y^{(2)}+11y^{(1)}-6y=0

The corresponding characteristic equation is

r^3-6r^2+11r-6=0

Three roots are

r_1=1

r_2=2

r_3=3

Then the solution for the homogeneous system is

y_c(t)=c_1e^{x}+c_2e^{2x}+c_3e^{3x}

where

y_1(t)=e^{x}

y_2(t)=e^{2x}

y_3(t)=e^{3x}

Then we follow to find the required solution to the nonhomogeneous equation. We use Variation of Parameters. We have

W[y_1,y_2,y_3]=2e^{6x}

W_1[y_1,y_2y_3]=e^{5x}

W_2[y_1,y_2y_3]=-2e^{4x}

W_3[y_1,y_2，y_3]=e^{3x}

and

g(x)=2\frac{e^{3x}}{e^{x}+1}

And then we have the following integration

\int \frac{W_1\cdot g(x)dx}{W[y_1,y_2,y_3]}=\int\frac{e^{2x}}{e^{x}+1}

\int\frac{e^{2x}}{e^{x}+1}=e^{x}-\ln(e^{x}+1)+c_4

\int \frac{W_2\cdot g(x)dx}{W[y_1,y_2,y_3]}=-2\int\frac{e^{x}}{e^{x}+1}

-2\int\frac{e^{x}}{e^{x}+1}=-2\ln(e^{x}+1)+c_5

\int \frac{W_3 \cdot g(x)dx}{W[y_1,y_2,y_3]}=\int\frac{1}{e^{x}+1}

\int\frac{1}{e^{x}+1}=x-\ln(e^{x}+1)+c_6

And finally, the required general solution $y(t)$

y(t)=\sum_{i=1}^3 y_i(t)\cdot\int\frac {W_i\cdot g(x)dx}{W[y_1,y_2,y_3]}
« Last Edit: April 11, 2018, 11:58:22 PM by Tim Mengzhe GENG »

#### Meng Wu

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##### Re: FE-P3
« Reply #2 on: April 11, 2018, 11:47:31 PM »
Small Error: $W_2(x)$ should be $2e^{4x}$.

#### Tim Mengzhe Geng

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##### Re: FE-P3
« Reply #3 on: April 11, 2018, 11:49:31 PM »
Small Error: $W_2(x)$ should be $2e^{4x}$.
For this case I don't think so since when we expand the matrix, we have to times $(-1)^{i+j}$

#### Meng Wu

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##### Re: FE-P3
« Reply #4 on: April 11, 2018, 11:54:19 PM »
Small Error: $W_2(x)$ should be $2e^{4x}$.
For this case I don't think so since when we expand the matrix, we have to times $(-1)^{i+j}$

Oh, you're right. My mistake.

#### Meng Wu

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##### Re: FE-P3
« Reply #5 on: April 11, 2018, 11:56:10 PM »
Also for $(20)$, $\ln(e^x)$ can be simplified as $\ln(e^x)=x$.

#### Tim Mengzhe Geng

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##### Re: FE-P3
« Reply #6 on: April 11, 2018, 11:57:57 PM »
Also for $(20)$, $\ln(e^x)$ can be simplified as $\ln(e^x)=x$.
Thanks again and I will modify it

#### Syed Hasnain

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##### Re: FE-P3
« Reply #7 on: April 12, 2018, 04:33:47 PM »
Since the solution is incomplete after Y(x),
I am attaching a copy of my solution
« Last Edit: April 13, 2018, 01:27:52 PM by Syed_Hasnain »

#### Tim Mengzhe Geng

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##### Re: FE-P3
« Reply #8 on: April 12, 2018, 10:01:46 PM »
Since the solution is incomplete after Y(x),
I am attaching a copy of my solution
Sorry what do you mean by "the solution is incomplete after Y(x)"
I did write a bit more on the exam (expanding the summation) but I think one should be able to get full marks if he integrates everything and mention how the solution is composed.(Given that the integral is correct)

#### Victor Ivrii

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##### Re: FE-P3
« Reply #9 on: April 15, 2018, 03:15:29 AM »
Since the solution is incomplete after Y(x),
I am attaching a copy of my solution
The only thing which was missing in the solution, is the final answer, but it warrants neither such claim, nor uploading your solution.

General remark:
It would be better to denote "parameters" by uppercase letters $C_1(x)$, $C_2(x)$,... and constants by lowercase letters $c_1$, $c_2$,...