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**Quiz-4 / Quiz 4 TUT 0702**

« **on:**October 18, 2019, 02:12:16 PM »

Find the general solution for y'' - 6y' + 9y = 0.

Solution:

changing it into characteristic equation it becomes:

r^2 - 6r + 9 = 0

(r-3)^2 = 0

r = 3

Hence y(t) = c_1e^(3t) + c_2te^(3t)

Solution:

changing it into characteristic equation it becomes:

r^2 - 6r + 9 = 0

(r-3)^2 = 0

r = 3

Hence y(t) = c_1e^(3t) + c_2te^(3t)