MAT244--2019F > Quiz-2

TUT0602 Quiz2

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Vickyyy:
Find the value of b of the given equation which is exact and then solve it using the value b.(ye2xy+x) + bxe2xyy' = 0M = ye2x + xN = bxe2xyMy = e2xy + 2xye2xyNx = be2xy + 2bxye2xySince My = Nx, b will equal to 1.M = ye2xy + x, N = xe2xyφx = M, φy = Nφx = ye2xy + xφ = ∫(ye2xy+x)dx = ye2xy/2y + x2/2 + h(y)φy = xe2xy + h'(y)φy = xe2xyh'(y) = 0, then h'(y) = cφ = e2xy/2 +x2/2 = c

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