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Tut0702 quiz3
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Topic: Tut0702 quiz3 (Read 4297 times)
shizhiwei
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Tut0702 quiz3
«
on:
October 11, 2019, 02:02:39 PM »
Find the general solution of the given differential equation:
4y'' - 9 y = 0
Solution:
4r^2 - 9 = 0
4r^2 = 9
r^2 = 9/4
r = +/- 3/2
r1 = 3/2
r2 = -3/2
Therefore, the general solution is y = C1e^3t/2 + C2e^-3t/2
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MAT244--2019F
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Tut0702 quiz3