Toronto Math Forum
Welcome,
Guest
. Please
login
or
register
.
1 Hour
1 Day
1 Week
1 Month
Forever
Login with username, password and session length
News:
Home
Help
Search
Calendar
Login
Register
Toronto Math Forum
»
MAT334--2020F
»
MAT334--Lectures & Home Assignments
»
Chapter 1
»
Solving roots of complex numbers
« previous
next »
Print
Pages: [
1
]
Author
Topic: Solving roots of complex numbers (Read 2972 times)
Maria-Clara Eberlein
Jr. Member
Posts: 11
Karma: 0
Solving roots of complex numbers
«
on:
September 20, 2020, 07:02:56 PM »
Suppose we want to solve for z=a+ib in an equation of the form z^n=w. After we find z in exponential representation, I am unsure of how to convert to z=a+ib form if theta is not one of the "special angles" we know the sin and cos of? Should we write z=rcos(theta)+i(rsin(theta)) without evaulating sin(theta) and cos(theta)?
Logged
RunboZhang
Sr. Member
Posts: 51
Karma: 0
Re: Solving roots of complex numbers
«
Reply #1 on:
September 20, 2020, 07:18:56 PM »
I think if the angle is unfamiliar, we can leave it as z=r[cos theta + i sin theta], otherwise we need to compute the value of sin and cos. Also, I think it has no difference with z=a+bi, it is just in the polar form.
Logged
Victor Ivrii
Administrator
Elder Member
Posts: 2607
Karma: 0
Re: Solving roots of complex numbers
«
Reply #2 on:
September 20, 2020, 07:46:18 PM »
The worst thing you can do is to use calculator to evaluate the value of, say, $\sin (4\pi/9)$ and $\cos (4\pi/9)$ numerically. But it may be useful to mention that
$\cos (4\pi/9)+i\sin (4\pi/9)$ belongs to the first quadrant and pretty close to $i$. Just draw a little picture.
Logged
Print
Pages: [
1
]
« previous
next »
Toronto Math Forum
»
MAT334--2020F
»
MAT334--Lectures & Home Assignments
»
Chapter 1
»
Solving roots of complex numbers