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**MAT244--Lectures & Home Assignments / Section4.4 Q11**

« **on:**October 31, 2018, 05:04:27 PM »

Find the solution of the given initial value problem:

y'''-y''+y'-y=sec(t), y(0)=2, y'(0)= -1, y''(0)=1

The solution manual writes "...with t(0)=0. Thus y(0) = c1+c2=2, y'(0)..." What does c1,c2 stand for?

y'''-y''+y'-y=sec(t), y(0)=2, y'(0)= -1, y''(0)=1

The solution manual writes "...with t(0)=0. Thus y(0) = c1+c2=2, y'(0)..." What does c1,c2 stand for?