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##### Test 2 / Misprints are possible

« Last post by**Victor Ivrii**on

*March 30, 2022, 07:17:41 PM*»

Misprints are possible

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Misprints are possible

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they defined up to a constant

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I am confused about the steps in Test 2 problem set Friday sitting question 4.

When dealing with the Fourier transform of the even continuation, in the second step, why x of the first part of the integral can be integrated out, but the second not. In other words, can someone explain to me how the second step's equation form based on the first step?

Thank you guys so much! I have attached the problem's picture below.

When dealing with the Fourier transform of the even continuation, in the second step, why x of the first part of the integral can be integrated out, but the second not. In other words, can someone explain to me how the second step's equation form based on the first step?

Thank you guys so much! I have attached the problem's picture below.

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In the practice term test 2 Variant A Problem 1, I had to solve the the following Sturm Liouville problem:

$$X''+\lambda x = 0$$ with boundary conditions $$X'(0) = X'(4\pi) = 0$$ In the answer key, the eigenfunction corresponding to the eigenvalue $\lambda_{0} = 0$ is $X_0 = \frac{1}{2}$. However, if we substituted $\lambda_0 = 0$ into the ODE, we get:

$$X'' = 0$$ which the solution is simply $$X(x) = \alpha + \beta x$$ Plugging into the boundary conditions and we get that $$\beta = 0$$ so The solution is $$X(x) = \alpha$$ where $\alpha \in \mathbb{R}$. How do we get that $ X_0 = \frac{1}{2}$?

$$X''+\lambda x = 0$$ with boundary conditions $$X'(0) = X'(4\pi) = 0$$ In the answer key, the eigenfunction corresponding to the eigenvalue $\lambda_{0} = 0$ is $X_0 = \frac{1}{2}$. However, if we substituted $\lambda_0 = 0$ into the ODE, we get:

$$X'' = 0$$ which the solution is simply $$X(x) = \alpha + \beta x$$ Plugging into the boundary conditions and we get that $$\beta = 0$$ so The solution is $$X(x) = \alpha$$ where $\alpha \in \mathbb{R}$. How do we get that $ X_0 = \frac{1}{2}$?

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Hi, I just want to confirm with someone about the solution for Term test 2 variant E problem2. I think for$\lambda_n$ the n should start from 0, so n should be n = 0, 1, 2 and so on. I don't know if the solution makes a typo or am I missing some insights here.

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Hi Professor,

I was reviewing practice test variant C problem4. I tried to follow your solution but I think where I circled should be the same as the other red circle? I don't know if this is a typo or am I missing some insights here. I've attached a picture.

Thank you

I was reviewing practice test variant C problem4. I tried to follow your solution but I think where I circled should be the same as the other red circle? I don't know if this is a typo or am I missing some insights here. I've attached a picture.

Thank you

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For problem 1 in Practice Test Variant E, I'm wondering if this is a typo because the interval given is from $-\pi$ to $\pi$? (I circled it in red)

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My question for Quiz5 was to decompose a function into full Fourier Series [0, $\pi$]. I wonder is it equivalent as decompose into full Fourier Series on [$-\pi$, $\pi$]?

Quote

I understand it is equivalent when the function is even, but I'm wondering what should I do when the function is odd.What is the problem? There are formulae for interval $[\alpha,\beta]$.

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My question for Quiz5 was to decompose a function into full Fourier Series [0, $\pi$]. I wonder is it equivalent as decompose into full Fourier Series on [$-\pi$, $\pi$]? I understand it is equivalent when the function is even, but I'm wondering what should I do when the function is odd.

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It is the derivative of Fourier transform; otherwise it would be $\widehat{f'}(k)$ and covered by another property