Toronto Math Forum
MAT244--2019F => MAT244--Test & Quizzes => Quiz-3 => Topic started by: YUTONG ZHANG on October 11, 2019, 02:01:36 PM
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Q: find the wronskian of the given pair of function:x, xe^x
Answer:
y1(x)=x
y1'(x)=1
y2(x)=xe^x
y2'(x)=e^x+xe^x
w= | x xe^x
1 e^x+xe^x |
=x(e^x+xe^x )-xe^x=xe^x+(x^2)(e^x)-xe^x
=(x^2)(e^x)