### Author Topic: 2.3 question 3  (Read 909 times)

#### Yan Zhou

• Full Member
• Posts: 15
• Karma: 1
##### 2.3 question 3
« on: February 10, 2020, 07:22:49 PM »
$$\int_{|z+1| = 2} \frac{zdz}{4-z^{2}} = \int_{|z+1| = 2} \frac{\frac{zdz}{2-z}}{2+z}$$
Since -2 lies in $|z+1| = 2$, Cauchy theorem gives that
$$\frac{1}{2\pi i} \int_{|z+1| = 2} \frac{\frac{zdz}{2-z}}{z-(-2)} = \frac{-2}{2-(-2)} = -\frac{1}{2}$$
then $$\int_{|z+1| = 2} \frac{zdz}{4-z^{2}} = -\pi i$$
However, I checked the answer of textbook and it says the answer is $2\pi i$, I am confused about where i did wrong.

#### Yan Zhou

• Full Member
• Posts: 15
• Karma: 1
##### Re: 2.3 question 3
« Reply #1 on: February 10, 2020, 07:46:22 PM »
I see. The question on the home assignment is a little bit different from the textbook.

#### Yan Zhou

• Full Member
• Posts: 15
• Karma: 1
##### Re: 2.3 question 3
« Reply #2 on: February 10, 2020, 08:11:40 PM »
I found some differences between textbook and home assignment, some of them are typos, and some do not affect the questions but the answers. Should we always follow the questions on the textbook?

#### Victor Ivrii

Your answer is correct ($-\pi i$).