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Messages - Fanxun Zeng

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16
Home Assignment 8 / Re: Problem 2
« on: November 28, 2012, 09:42:03 PM »
Dear Ian Kivlichan: can you please check what I posted above is solution for part c?
I think it only asks us to formulate similar statements, without proof, so I type tyem.

17
Home Assignment 8 / Re: Problem 3
« on: November 28, 2012, 09:35:47 PM »
Problem 3 part a maximum principle solution attached mimimum principle is similar

18
Home Assignment 8 / Re: Problem 1
« on: November 28, 2012, 09:32:25 PM »
Problem 1 part b solution attached

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Home Assignment 8 / Re: Problem 1
« on: November 28, 2012, 09:31:54 PM »
Problem 1 part a solution attached

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Home Assignment 8 / Re: Problem 3
« on: November 28, 2012, 09:31:20 PM »
Problem 3 part a solution attached

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Home Assignment 8 / Re: Problem 2
« on: November 28, 2012, 09:30:38 PM »
Problem 2 part c solution attached

22
Home Assignment 8 / Problem 4
« on: November 28, 2012, 09:29:25 PM »
Just to note, homework 8 PDF states Newton Screening theorem is in L26 in fact it is in L27.

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Home Assignment 8 / Problem 3
« on: November 28, 2012, 09:28:25 PM »
Problem 3 Solutions posting after 21:30 Edit: following professor's advice, web link:
http://www.math.toronto.edu/courses/apm346h1/20129/HA8.html#problem-8.3

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Home Assignment 8 / Problem 2
« on: November 28, 2012, 09:28:03 PM »

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Home Assignment 8 / Problem 1
« on: November 28, 2012, 09:27:32 PM »
Problem 1 a b required c d bonus Solutions posting after 21:30

Is it a flood? You could at least post a link

http://www.math.toronto.edu/courses/apm346h1/20129/HA8.html#problem-8.1

And guys, don't start new topics for the same question-I merged all. V.I.

26
Home Assignment 7 / Re: Problem 1
« on: November 19, 2012, 09:30:30 PM »
Problem 1 b solution attached

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Home Assignment 7 / Re: Problem 1
« on: November 19, 2012, 09:29:56 PM »
Problem 1 a solution attached

28
Home Assignment 6 / Re: Problem 4
« on: November 07, 2012, 10:44:17 PM »
Thanks professor. For parts a and b denominator issues maybe 3 TAs can vote for either deduction or bonus for who did right, we students don't discuss here. Correction: as PDF can't be displayed and need to be downloaded, for convenience, in fact what I posted at 10:05pm above is not in PDF but in JPG. Mine is complete a b c solutions I edited from Calvin's incomplete one.

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Home Assignment 6 / Re: Problem 2
« on: November 07, 2012, 10:26:05 PM »
I agree with Ziting Zhou that we CAN divide 4 cases in part d if we wish, exactly what I did. Let me show mathematically what the four cases are: 1) w> Î²>0 2) Î² > w > 0 3) w<0 and |w|<|Î²| 4) w<0 and |w|>|Î²|  if we do want to divide. Thanks!

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Home Assignment 6 / Re: Problem 4
« on: November 07, 2012, 10:05:28 PM »
Thanks professor. As I originally suggested, we do need to add k=0 to get complete answer, otherwise mark should be deducted for anyone not considering that, as it's not completely correct, as mathematics is a serious academic field and a denominator cannot be zero! Bonus mark: I have spent half an hour to edited Calvin's incomplete solution as PDF attached for both a and b to get corrected a b c, especially showing how to mathematically get F(k) in case of k=0. Thanks for karma!

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