### Author Topic: Problem 2  (Read 11616 times)

#### Peishan Wang

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##### Problem 2
« on: October 30, 2012, 11:36:54 AM »
Hi Professor,

I'm not sure if there's a typo but in Problem 2 I think we should be given a specific interval (say [-pi, pi]) in order to plot the graph. Thanks!

#### Victor Ivrii

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##### Re: Problem 2
« Reply #1 on: October 30, 2012, 12:29:38 PM »
You have $[-l,l]$ and you may plot for any value $l>0$ (say $l=1$)

#### Aida Razi

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##### Re: Problem 2
« Reply #2 on: October 31, 2012, 09:30:42 PM »
Part (c) solution is attached!

#### Victor Ivrii

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##### Re: Problem 2
« Reply #3 on: November 01, 2012, 01:57:35 AM »
Wher are calculatingly simpler  a), b)? And the sketch?

#### Aida Razi

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##### Re: Problem 2
« Reply #4 on: November 04, 2012, 02:39:59 PM »
Part (a) solution is attached!

#### Aida Razi

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##### Re: Problem 2
« Reply #5 on: November 05, 2012, 01:53:33 AM »
Part (b) solution is attached!

#### Zarak Mahmud

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##### Re: Problem 2
« Reply #6 on: November 06, 2012, 06:17:44 PM »
Since $f(x) = x^2$ was already computed in part c, to calculate part a (say $g(x) = x$), we could have also noted that $$g(x) = \frac{1}{2}\frac{d}{dx}f(x)$$ and applied this transformation term by term to the Fourier series of $f(x)$.