MAT244-2013F > MidTerm

MT, P1

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Victor Ivrii:
Solve the following initial value problem:
\begin{equation*}
y'(t) = 1- y^2(t),\qquad y(0)=0.
\end{equation*}

Yangming Cai:
answer to p1

Xiaozeng Yu:
1

Xuewen Yang:
For Xiaozeng Yu,

Is there a problem with the sign change? from "plus" (2nd row) to "minus" (3rd row) ?

Xiaozeng Yu:

--- Quote from: Xuewen Yang on October 09, 2013, 10:47:45 PM ---For Xiaozeng Yu,

Is there a problem with the sign change? from "plus" (2nd row) to "minus" (3rd row) ?

--- End quote ---

no mistake. $d(\ln(1-y))/dt = -1/(1-y)$.

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