MAT244--2018F > Quiz-5
Q5 TUT 0801
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Victor Ivrii:
Transform the given initial value problem into an initial value problem for two first order equations.
$$\left\{\begin{aligned}
&u'' + 0.25u' + 4u = 2 \cos (3t),\\
&u(0) = 1,\qquad u'(0) = -2.
\end{aligned}\right.$$
Guanyao Liang:
Answer in the attachment.
Zhiya Lou:
Let $x_1= u, x_2=u'$
Then substitute it into original equation:
$ x_2'+0.25x_2+4x_1 = 2\cos(3t)$
So, we can transform into the system:
$x_1'=x_2$
$ x_2'+0.25x_2+4x_1 = 2\cos(3t)$
With given initial value:$x_1(0)=1, x_2(0)= -2$
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