Author Topic: Q1-T0801  (Read 1778 times)

Victor Ivrii

  • Administrator
  • Elder Member
  • *****
  • Posts: 2563
  • Karma: 0
    • View Profile
    • Personal website of Victor Ivrii
Q1-T0801
« on: January 25, 2018, 08:16:13 AM »
Find the general solution of the given equation:
\begin{equation*}
xy' = (1 - y^2)^{1/2}.
\end{equation*}

Junya Zhang

  • Full Member
  • ***
  • Posts: 27
  • Karma: 29
    • View Profile
Re: Q1-T0801
« Reply #1 on: January 25, 2018, 08:58:51 AM »
« Last Edit: January 25, 2018, 09:20:33 AM by Junya Zhang »

Tiange Gao

  • Newbie
  • *
  • Posts: 2
  • Karma: 0
    • View Profile
Re: Q1-T0801
« Reply #2 on: January 25, 2018, 03:51:40 PM »
Should |y| be less than 1?