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### Messages - Suheng Yao

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##### Chapter 2 / Little questions about quiz coverage
« on: September 22, 2020, 05:33:15 PM »
I noticed that on qurcus, it said that the quiz would be one problem from Home Assignments to Week 2. But by the email from the professor, the Bernoulli function is covered in the quiz, but the home assignment for Bernoulli function is actually not in week 2. So do I need to finish doing problems to section 2.4 to prepare for the quiz?

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##### Chapter 2 / Re: section 2.1 practice problem 15
« on: September 19, 2020, 11:27:52 PM »
Sorry, but I think that I still did not get the idea. I understood the part that x cannot equal to 15^(1/2)/2. But why does y' is greater than 0 at every defined point? I had plotted the graph, but I didn't seem to understand.

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##### Chapter 2 / Re: section 2.1 practice problem 35
« on: September 19, 2020, 05:45:09 PM »
Thanks, and in tests, could we leave the answer in the implicit equation form? Or is it necessary to transform it into a parametric form as the professor taught in the class?

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##### Chapter 2 / section 2.1 practice problem 35
« on: September 19, 2020, 04:52:11 PM »
I had solved this equation to this implicit form, but I don't know how to simplify to a simpler form as the answer shown. Could someone help me? Thanks.

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##### Chapter 2 / section 2.1 practice problem 15
« on: September 19, 2020, 04:44:14 PM »
For this question, I need to get an interval where the solution is defined. However, for the interval of x, I got x>=sqrt(15)/2 or x<=-sqrt(15)/2, but the answer only has x>sqrt(15)/2. I don't know why. Could anyone help me?

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##### Chapter 2 / Re: Boyce-DiPrima Section 2.1 Example 1
« on: September 15, 2020, 02:51:19 PM »
I think that the textbook just uses the product rule: [f*g]=f'*g+g'*f. Here, you can think f as 4+t^2 and g as y. Hope this helps.

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##### Chapter 2 / Re: Lecture 0201 question
« on: September 15, 2020, 02:23:46 PM »
Thanks, prof. Also, on the next slide, I feel confused about why does f(x) have a single minimum at x=a and have equilibrium at x=a and y=b? I really don't get the idea here.

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##### Chapter 2 / Lecture 0201 question
« on: September 15, 2020, 12:24:18 PM »
This is the last question from yesterday's lecture 0201 section. I still don't understand why there is a negative sign on the right side of the equation?

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